Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers.
If such arrangement is not possible, it must rearrange it as the lowest possible order (ie, sorted in ascending order).
The replacement must be in-place, do not allocate extra memory.
Here are some examples. Inputs are in the left-hand column and its corresponding outputs are in the right-hand column.
1,2,3 → 1,3,2
3,2,1 → 1,2,3
1,1,5 → 1,5,1
题目大意：实现下一个排列，也就是按照字典序的下一个比它大的排列～
分析：用C++库函数作个弊。。。
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class Solution { public: void nextPermutation(vector<int>& nums) { next_permutation(nums.begin(), nums.end()); } }; |
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