In computer science, a heap is a specialized tree-based data structure that satisfies the heap property: if P is a parent node of C, then the key (the value) of P is either greater than or equal to (in a max heap) or less than or equal to (in a min heap) the key of C. A common implementation of a heap is the binary heap, in which the tree is a complete binary tree. (Quoted from Wikipedia at https://en.wikipedia.org/wiki/Heap_(data_structure))
Your job is to tell if a given complete binary tree is a heap.
Input Specification:
Each input file contains one test case. For each case, the first line gives two positive integers: M (<= 100), the number of trees to be tested; and N (1 < N <= 1000), the number of keys in each tree, respectively. Then M lines follow, each contains N distinct integer keys (all in the range of int), which gives the level order traversal sequence of a complete binary tree.
Output Specification:
For each given tree, print in a line “Max Heap” if it is a max heap, or “Min Heap” for a min heap, or “Not Heap” if it is not a heap at all. Then in the next line print the trees postorder traversal sequence. All the numbers are separated by a space, and there must no extra space at the beginning or the end of the line.
Sample Input:
3 8
98 72 86 60 65 12 23 50
8 38 25 58 52 82 70 60
10 28 15 12 34 9 8 56
Sample Output:
Max Heap
50 60 65 72 12 23 86 98
Min Heap
60 58 52 38 82 70 25 8
Not Heap
56 12 34 28 9 8 15 10
题目大意:给一个树的层序遍历,判断它是不是堆,是大顶堆还是小顶堆。输出这个树的后序遍历~
分析:30分大题,25行代码,一行代码一分……((⊙o⊙)嗯) // 我为什么这么机智可爱又伶俐?
从后往前检查所有节点(除了根节点)和它的父节点的关系,判断是否破坏最大堆或者最小堆的性质,如果有不满足的情况将maxn或minn置为0,以此排除最大堆或者最小堆~
然后后序遍历,对于index结点分别遍历孩子index*2和右孩子index*2+1,遍历完左右子树后输出根结点~
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 |
#include <iostream> using namespace std; int a[1005], m, n; void postOrder(int index) { if (index > n) return; postOrder(index * 2); postOrder(index * 2 + 1); printf("%d%s", a[index], index == 1 ? "\n" : " "); } int main() { scanf("%d %d", &m, &n); while (m--) { int minn = 1, maxn = 1; for (int i = 1; i <= n; i++) scanf("%d", &a[i]); for (int i = 2; i <= n; i++) { if (a[i] > a[i / 2]) maxn = 0; if (a[i] < a[i / 2]) minn = 0; } if (maxn == 1) printf("Max Heap\n"); else if (minn == 1) printf("Min Heap\n"); else printf("Not Heap\n"); postOrder(1); } return 0; } |
❤ 点击这里 -> 订阅《PAT | 蓝桥 | LeetCode学习路径 & 刷题经验》by 柳婼