LeetCode 1. Two Sum – 柳婼の blog

Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution.

Example:
Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].
UPDATE (2016/2/13):
The return format had been changed to zero-based indices. Please read the above updated description carefully.

class Solution {
public:
    vector<int> twoSum(vector<int>& nums, int target) {
        vector<int> v(2);
        for(int i = 0; i < nums.size(); i++) {
            for(int j = i + 1; j < nums.size(); j++) {
                if(nums[i] + nums[j] == target) {
                    v[0] = i;
                    v[1] = j;
                }
            }
        }
        return v;
    }
};

class Solution {

public:

vector<int> twoSum(vector<int>& nums, int target) {

vector<int> v(2);

for(int i = 0; i < nums.size(); i++) {

for(int j = i + 1; j < nums.size(); j++) {

if(nums[i] + nums[j] == target) {

v[0] = i;

v[1] = j;

}

return v;

}

};

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