设计复数库，实现基本的复数加减乘除运算。
输入时只需分别键入实部和虚部，以空格分割，两个复数之间用运算符分隔；输出时按a+bi的格式在屏幕上打印结果。参加样例输入和样例输出。
注意考虑特殊情况，无法计算时输出字符串”error”。
样例输入
2 4 * -3 2
样例输出
-14-8i
样例输入
3 -2 + -1 3
样例输出
2+1i
分析：除法的时候有点麻烦，结果要变成浮点型，因为测试用例的答案是统一输出一位有效数字的。。所以0.123输出0.1 1.000输出1。。。我用了cout的setprecision控制输出的有效数字个数~
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#include <iostream> #include <iomanip> using namespace std; void add(int a, int b, int m, int n); void min(int a, int b, int m, int n); void multi(int a, int b, int m, int n); void div1(int a, int b, int m, int n); int main() { int a,b,m,n; char c; cin >> a >> b; cin >> c; cin >> m >> n; switch(c) { case '+': add(a, b, m, n); break; case '-': min(a, b, m, n); break; case '*': multi(a, b, m, n); break; case '/': div1(a, b, m, n); break; } return 0; } void add(int a, int b, int m, int n) { int l, r; l = a + m; r = b + n; if (l != 0){ if (r != 0) { if (r > 0) cout << l << "+" << r << "i"; else cout << l << r << "i"; } else { cout << l; } } else { if (r != 0) { cout << r << "i"; } else { cout << 0; } } } void min(int a, int b, int m, int n) { int l, r; l = a - m; r = b - n; if (l != 0) { if (r != 0) { if (r > 0) cout << l << "+" << r << "i"; else cout << l << r << "i"; } else { cout << l; } } else { if (r != 0) { cout << r << "i"; } else { cout << 0; } } } void multi(int a, int b, int m, int n) { int l, r; l = a * m - b * n; r = a * n + b * m; if (l != 0) { if (r != 0) { if (r > 0) cout << l << "+" << r << "i"; else cout << l << r << "i"; } else { cout << l; } } else { if (r != 0) { cout << r << "i"; } else { cout << 0; } } } void div1(int a, int b, int m, int n) { if (m == 0 && n == 0) { cout << "error"; } else { double l, r; l = (double)(a * m + b * n) / (m * m + n * n); r = (double)(b * m - a * n) / (m * m + n * n); if (l != 0) { if (r != 0) { if (r > 0) { cout << setprecision(1) << l << "+" << r << endl; } else { cout << setprecision(1) << l << r << "i" << endl; } } else { cout << setprecision(1) << l << endl; } } else { if (r != 0) { cout << setprecision(1) << r << "i" << endl; } else { cout << 0; } } } } |