LeetCode 47. Permutations II

Given a collection of numbers that might contain duplicates, return all possible unique permutations.

For example,
[1,1,2] have the following unique permutations:
[
[1,1,2],
[1,2,1],
[2,1,1]
]

题目大意：返回一个数字集合构成的数字（可能有重复数字）的所有可能的唯一的全排列～

分析：先对nums排序，然后将所有全排列加入result中～

class Solution {
public:
    vector<vector<int>> permuteUnique(vector<int>& nums) {
        vector<vector<int>> result;
        sort(nums.begin(), nums.end());
        do {
            result.push_back(nums);
        } while (next_permutation(nums.begin(), nums.end()));
        return result;
    }
};

class Solution {

public:

vector<vector<int>> permuteUnique(vector<int>& nums) {

vector<vector<int>> result;

sort(nums.begin(), nums.end());

do {

result.push_back(nums);

} while (next_permutation(nums.begin(), nums.end()));

return result;

}

};

❤ 点击这里 -> 订阅《PAT | 蓝桥 | LeetCode学习路径 & 刷题经验》by 柳婼

❤ 点击这里 -> 订阅《从放弃C语言到使用C++刷算法的简明教程》by 柳婼

❤ 点击这里 -> 订阅PAT甲级乙级、蓝桥杯、GPLT天梯赛、LeetCode题解离线版