1015. Reversible Primes (20)
A reversible prime in any number system is a prime whose “reverse” in that number system is also a prime. For example in the decimal system 73 is a reversible prime because its reverse 37 is also a prime.
Now given any two positive integers N (< 105) and D (1 < D <= 10), you are supposed to tell if N is a reversible prime with radix D.
Input Specification:
The input file consists of several test cases. Each case occupies a line which contains two integers N and D. The input is finished by a negative N.
Output Specification:
For each test case, print in one line “Yes” if N is a reversible prime with radix D, or “No” if not.
Sample Input:
73 10
23 2
23 10
-2
Sample Output:
Yes
Yes
No
题目大意:如果一个数本身是素数,而且在d进制下反转后的数在十进制下也是素数,就输出Yes,否则就输出No
PS:感谢github用户@fs19910227提供的pull request~
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import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.math.BigInteger; public class Main { private boolean isPrime(String number) { int value = Integer.valueOf(number); if (value <= 1) return false; if (value == 2) return true; if (value % 2 == 0) return false; int maxLimit = (int) Math.sqrt(value); for (int i = 3; i <= maxLimit; i += 2) { if (value % i == 0) { return false; } } return true; } private String reversePrime(String number, int radix) { int value = Integer.valueOf(number); StringBuilder builder = new StringBuilder(); for (; value != 0; value = value / radix) { int bit = value % radix; builder.append(bit); } return new BigInteger(builder.toString(), radix).toString(); } public static void main(String[] args) throws IOException { BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); Main rp = new Main(); String[] split = reader.readLine().split(" "); for (; split.length > 1; split = reader.readLine().split(" ")) { String number = split[0]; int radix = Integer.valueOf(split[1]); if (rp.isPrime(number) && rp.isPrime(rp.reversePrime(number, radix))) { System.out.println("Yes"); } else { System.out.println("No"); } } } } |
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