LeetCode 100. Same Tree – 柳婼の blog

Given two binary trees, write a function to check if they are equal or not.

Two binary trees are considered equal if they are structurally identical and the nodes have the same value.

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    bool isSameTree(TreeNode* p, TreeNode* q) {
        if(p != NULL && q != NULL)
            return p->val == q->val && isSameTree(p->left, q->left) && isSameTree(p->right, q->right);
        return p == NULL && q == NULL;
    }
};

/**

* Definition for a binary tree node.

* struct TreeNode {

* int val;

* TreeNode *left;

* TreeNode *right;

* TreeNode(int x) : val(x), left(NULL), right(NULL) {}

* };

class Solution {

public:

bool isSameTree(TreeNode* p, TreeNode* q) {

if(p != NULL && q != NULL)

return p->val == q->val && isSameTree(p->left, q->left) && isSameTree(p->right, q->right);

return p == NULL && q == NULL;

}

};

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