LeetCode 136. Single Number

Given an array of integers, every element appears twice except for one. Find that single one.

Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

class Solution {
public:
    int singleNumber(vector<int>& nums) {
        sort(nums.begin(), nums.end());
        for(int i = 0; i < nums.size() - 1; i = i + 2) {
            if(nums[i] != nums[i + 1]) {
                return nums[i];
            }
        }
        return nums[nums.size() - 1];
    }
};

class Solution {

public:

int singleNumber(vector<int>& nums) {

sort(nums.begin(), nums.end());

for(int i = 0; i < nums.size() - 1; i = i + 2) {

if(nums[i] != nums[i + 1]) {

return nums[i];

}

return nums[nums.size() - 1];

}

};

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